Given:

The scores on the four college algebra exams are 82, 96, 91 and 92.

Approach:

Let’s assume that a student needs to score xon the fifth exam.

We will use the following formula for calculating average.

Average=Sum of scores/Number of exams

Calculation:

Average = Sum of scores/Number of exams

\(90=\frac{82+96+91+92+x}{5}\)

\(90=\frac{361+x}{5}\)

\(90\times 5=361=x\)

\(450=361+x\)

x=450-361

x=89

Final Statement

A student needs to score 89 on the fifth college exam.

The scores on the four college algebra exams are 82, 96, 91 and 92.

Approach:

Let’s assume that a student needs to score xon the fifth exam.

We will use the following formula for calculating average.

Average=Sum of scores/Number of exams

Calculation:

Average = Sum of scores/Number of exams

\(90=\frac{82+96+91+92+x}{5}\)

\(90=\frac{361+x}{5}\)

\(90\times 5=361=x\)

\(450=361+x\)

x=450-361

x=89

Final Statement

A student needs to score 89 on the fifth college exam.