Lagrange remainder vs. Alternating Series Estimation Theorem: do they always provide the same error bound? If a function has a nth degree Taylor series approximation, we can use the Lagrange form of the remainder to calculate the maximum value of the error of approximation. If the series is also an alternating series, we can use the Alternating Series Estimation Theorem to get another maximum value of the error of approximation. It is not guaranteed that the two maximums will always be the same.

chchchchinacjn

chchchchinacjn

Answered question

2022-12-18

Lagrange remainder vs. Alternating Series Estimation Theorem: do they always provide the same error bound?
If a function has a nth degree Taylor series approximation, we can use the Lagrange form of the remainder to calculate the maximum value of the error of approximation. If the series is also an alternating series, we can use the Alternating Series Estimation Theorem to get another maximum value of the error of approximation. It is not guaranteed that the two maximums will always be the same.

Answer & Explanation

Ayanna Alexander

Ayanna Alexander

Beginner2022-12-19Added 4 answers

They will not be the same. One example to the contrary is all that is needed. Use cos ( x ) = 1 x 2 2 ! + . . . Suppose you want to evaluate cos ( 0.1 ), error using first dropped term 0.1 4 4 ! , and using LaGrange Error is 0.1 3 3 !

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